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Математика 4-7 класс Amirkhan

33/(1 + (30/(x + 2))) = 3
240/(((2x - 10)/5) - 4) = 40
1450/(1 + (56/(8 - (54 / (6 + (12/1450 - x)))))) = 50

Ответы:

1) 33/(1 + (40/(x + 2))) = 3

33 = 3(1 + (40/(x + 2)))

33 = 3 + 120/(x + 2)

30 = 120/(x + 2)

30(x + 2) = 120

30x + 60 = 120

30x = 60

x = 2

2) 240/(((2x - 10)/5) - 4) = 40

240 = 40(((2x - 10)/5 ) - 4)

240 = 16x - 80 - 160

-16x = -480

x = 30

3) 1450/(1 + (56/(8 - (54 / (6 + (12/1450 - x)))))) = 50

1/(1 + (56/(8 - (54 / (6 + (12/1450 - x)))))) = 50/1450

1/(1 + (56/(8 - (54 / (6 + (12/1450 - x)))))) = 1/29

1 + (56/(8 - (54 / (6 + (12/1450 - x))))) = 29

56/(8 - (54 / (6 + (12/1450 - x)))) = 28

1/(8 - (54 / (6 + (12/1450 - x)))) = 28/56

8 - (54 / (6 + (12/1450 - x))) = 2

(54 / (6 + (12/1450 - x))) = 6

(1/(6 + (12/1450 - x))) = 6/54

6 + (12/1450 - x) = 9

(12/(1450 - x)) = 3

(1/(1450 - x)) = 3/12

(1450 - x) = 4

x = 1446

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